Complex Number Play

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⌘支持系统: OS X 10.11
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1)You can find mod [3(cos30-isin30)]m conjugate [3(cos30-isin30)]c inverse [3(cos30-isin30)]i 2)And you can do Addition [3(cos30-isin30)]+[4-i7] Subtraction [3(cos30-isin30)]-[4-i7] Multiplication [3(cos30-isin30)]*[4-i7] Division [3(cos30-isin30)]/[4-i7] any power [3(cos30-isin30)]p[7] any number of roots [3(cos30-isin30)]r[5] You can prefer polar calculations or normal. You can do calculations with Degree or Radiant.
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